The speed of the elevator is irrelevant. I heard that it is the net of all forces acting on the object in the vertical direction? on your scales at home to see your apparent weight change, while your weight (and mass) stays the same. It is the acceleration of the lift which is important not the direction of travel of the lift. Scales can measure the force of gravity but they can also be fooled, because they measure any "downwards force" and don't know if it is gravity or some other force. Here is how much the apparent weight of a man is in a lift or elevator. Do you mean the object is exposed to inertia ? Does countably infinite number of zeros add to zero? Fy = m x ay R - mg = 0 R = mg Why can we add/substract/cross out chemical equations for Hess law? whereas, in an elevator which is undergoing an upward acceleration, the magnitude of the normal force increases rather than decreasing. It all depends on the situation and how you set the definition for the apparent weight. The weight shown on a scale is equal in magnitude, but opposite in direction, to the normal force. Regex: Delete all lines before STRING, except one particular line. Many people are already aware that there is an attraction force known as gravity that draws everyone towards the center of the earth. How come $N \cos \theta=W$ if $N=W \cos \theta$ for the motion on a banked road? Which force does a weighing scale measure? What is the apparent weight of a sinking body? Why does the normal force go down in an downward accelerating elevator? Note that the mass is property of a body which does not depend on the frame of reference. Buoyancy is responsible for this upward force. To maybe extend @user253751's comment, imagine a third image in which the rope is attached to the person. Thanks for contributing an answer to Physics Stack Exchange! Is there a trick for softening butter quickly? What is the direction and magnitude of the elevator's acceleration. Non-anthropic, universal units of time for active SETI, Horror story: only people who smoke could see some monsters. Is there a universal formula for finding the apparent weight of an object in a particular situation? The Earth's mass of 5,973,600,000,000,000,000,000,000kg pulls objects towards it with quite a large force! Is MATLAB command "fourier" only applicable for continous-time signals or is it also applicable for discrete-time signals? If your first picture's object was hollow and there was a ball inside, and you started lifting the object, its normal force to the ball would have to increase, just like in the elevator example, in order to accelerate the ball. In the first picture, the block is like the person, and the floor is like the elevator. In the elevator's case, the elevator is pushing the person up, so you can think of the atoms of the person's feet getting closer to the atoms of the elevator pushing the person act, hence the increase in the repulsive force. Elevator going up and slowing down: N = mg m|a|. When an elevator first begins to descend, you feel lighter, whereas when it slows down again and moves upward steadily, you feel heavier. Raising an object https://physics.stackexchange.com/a/681282/149541, Mobile app infrastructure being decommissioned. Homework Statement An object is placed on a scale in an elevator which reads 8kg at rest. How can i extract files in the directory where they're located with the find command? When the frame of reference accelerates up, you have to apply pseudo forces in the opposite direction of the motion of the frame of reference. The most important thing is to set the definition for the apparent weight. faster and faster downwards the scales show less! You must specify this in yur edit. Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. But didn't you already give a definition yourself :"The apparent weight is the force with which person acts on the floor which is by Newton's third law the same as the force with which floor acts on the person." Question: What happens to the apparent weight when the elevator accelerates UP? If an upward force was applied on an object which was at rest, the magnitude of the normal force decreases. If, however, your object of interest is the elevator itself (together with the person inside), then as the elevator cable pulls everything up, the elevator starts rising, and the normal force exerted by the ground on the elevator box decreases, and eventually becomes zero - which is analogous to what happens with the block. The intermolecular repulsive force in your macroscopic elevator/block case is what you call the normal force. This scale shows 9.2kg when the elevator accelerates. Note that the intermolecular repulsive force increases when atoms get closer together (due to their charge). If your first picture's object was hollow and there was a ball inside, and you started lifting the object, its normal force to the ball would have to increase, just like in the elevator example, in order to accelerate the ball. Wa= Wreal+ m*a Where Wais the apparent weight Wrealis the "real" weight. To learn more, see our tips on writing great answers. Why is there a downward apparent force on an object accelerating upwards in an elevator? In the second image, the normal force is exerted by the elevator floor (from the inside), and is acting on the person. If the elevator is moving at a constant speed there is no difference in the apparent weight compared to when it is sitting still. The (True) weight, of course, is mg. Problem setting number formatting in Table output after using estadd/esttab. What is the apparent weight of the object when it reaches the terminal velocity? The situation is subtly different in that now there are only two forces acting on the object as there is now no $F_{\rm pull}$ and $F_{\rm N}$ is the upward force which can produce an acceleration of the object. In this case, you are actually separating the two surfaces in contact by pulling the block up and not moving the floor and due to this the intermolecular distances (between the two) increases and hence the normal force (between the two surfaces) decreases. Making statements based on opinion; back them up with references or personal experience. See related discussion: Is there a formal definition for apparent weight? It's not the whole elevator that's being considered. "Sum of all forces" makes no sense. $F_\mathrm{app}
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